2x-((3x^2)/36)

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Solution for 2x-((3x^2)/36) equation:


x in (-oo:+oo)

2*x-((3*x^2)/36) = 0

(-1/12)*x^2+2*x = 0

2*x-1/12*x^2 = 0

DELTA = 2^2-(-1/12*0*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-2)/(-1/12*2) or x = (-4^(1/2)-2)/(-1/12*2)

x = 0 or x = 24

x in { 0, 24 }

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